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Old 01-18-2011, 02:20 AM   #11
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Col. Mustard in the kitchen with a lead pipe. I think (And that is very rare) that the remainder of the .45 round will actually carry portions of the 9mm projectile on down the original line of the .45.

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Old 01-18-2011, 02:23 AM   #12
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They will hit and due to the spin of the bullets going in opposite directions they will cause a vortex to form with the following data set. delta x over delta y * the cube of pi divided by in domains of the middle star in orion's belt to the 5th power.

thus causing a freak rupture in space time allowing our universe to bleed into an alternate one thus causing the implosion not only of earth but of our entire galaxy.

So I caution you from trying to do this.

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Old 01-18-2011, 03:04 AM   #13
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Quote:
Originally Posted by sweeper22 View Post
Only this guy could tell you...



BTW- Both bullets better be flat-nosed.
I would ask him but I think somehow at the end of the equation the answer will always be "1985"
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Old 01-18-2011, 03:52 AM   #14
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I wanna know how they meet in the middle when fired exactly at the same time and the velocities are different. The premise is flawed.

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Old 01-18-2011, 04:39 AM   #15
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The answer is muzzle energy...the round with the bigger number wins...

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Old 01-18-2011, 05:12 AM   #16
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The answer is muzzle energy...the round with the bigger number wins...
Right, velocity and weight. But they won't meet in the middle according to the premise. The faster one travels a greater distance, so how can you accurately account for velocity loss over distance travelled. Change the premise to same distance travelled and time out the firings of the rounds and compensate for energy lost due to drag.

I don't wanna make the op nuts over this, but if you wanna be scientific about it...

1. Formulate a hypothesis
2. Run tests that will prove or disprove the hypothesis
3. Record the datum
4. Objectively report based on nothing but scientific data
5. Proclaim proof of genius or idiocy
6. Re-run tests because you just wanna
7. Proclaim otherwise as to your prior claim of idiocy
8. Manipulate the data to support your claim of genius
9. Ignore claims of otherwise
10. Enjoy only 1 term as the 44th POTUS

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Old 01-18-2011, 05:30 AM   #17
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To go with skullys thing. They would not meet in the middle

the 45acp would have traveled 12.3' and the 9mm would have traveled 17.7' (Aprox)

Energy of the 45acp at 4 yards is 333 ft lbs and the 9mm at 6 yards is 326ft lbs.

Not a whole lot of difference. but colliding they would have 659 ft lbs of energy. More than likely both bullets if they hit perfectly square nose to nose in a perfect walgreens world they would just explode with the 45acp winning over by maybe a little more but most of your shards are going to be sitting 12.3' from the 45 acp guy and 17.7' from then 9mm guy.

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Old 01-18-2011, 02:31 PM   #18
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The guy who carries a .45acp is obviously more skilled than the guy who chooses a 9mm so obviously .45 guy will get the shot off first thus meeting the bullets in the exact middle.
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Old 01-18-2011, 04:35 PM   #19
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The REAL question here is, who gets off the follow up shot faster? My money is on the fellow with the 9mm.

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Old 01-18-2011, 04:54 PM   #20
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The REAL question here is, who gets off the follow up shot faster? My money is on the fellow with the 9mm.

Nah. It depends on the shooter, the weapon, and what tango is wearing.
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