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Old 03-29-2012, 09:32 PM   #11
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Quote:
Originally Posted by Yunus

Same per ticket but if you have 2 tickets you have 2 chances.
Odds remain the same. Otherwise, the "1:189,000,000 odds (or whatever they are) would mean, buy that many tickets and you're a guaranteed winner. Sorry, doesn't work that way.

The odds are the same, no matter the number of tix purchased, counterintuitive as that may be.
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Old 03-29-2012, 10:20 PM   #12
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Quote:
Originally Posted by Chandler51

Odds remain the same. Otherwise, the "1:189,000,000 odds (or whatever they are) would mean, buy that many tickets and you're a guaranteed winner. Sorry, doesn't work that way.

The odds are the same, no matter the number of tix purchased, counterintuitive as that may be.
So if there are 19 black marbles and 1 white marble in a hat. My odds are the same for picking the white marble, no matter how many tries I get? This is alittle easier to get my head around.
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Old 03-29-2012, 10:22 PM   #13
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This reminds me of a conversation I had about deal or no deal. Lol

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Old 03-29-2012, 10:42 PM   #14
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Quote:
Originally Posted by downsouth

So if there are 19 black marbles and 1 white marble in a hat. My odds are the same for picking the white marble, no matter how many tries I get? This is alittle easier to get my head around.
I'm glad you got it cuz you just lost me...
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Old 03-29-2012, 10:45 PM   #15
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Quote:
Originally Posted by Chandler51

I'm glad you got it cuz you just lost me...
Are my overall odds the same to pick the white marble if I try once or one hundred times before I quit trying. Does that help?
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Old 03-30-2012, 12:09 AM   #16
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Quote:
Originally Posted by Chandler51 View Post
Odds remain the same. Otherwise, the "1:189,000,000 odds (or whatever they are) would mean, buy that many tickets and you're a guaranteed winner. Sorry, doesn't work that way.

The odds are the same, no matter the number of tix purchased, counterintuitive as that may be.
That's exactly how it works. There are 175,711,536 combinations possible. Buy all the possible combinations and your combined odds of winning are 175,711,536:175,711,536 or 1:1. You can't simply "buy that many tickets" you would need to buy that many tickets with no duplicates.

http://mathforum.org/library/drmath/view/56691.html

For a really interesting concept that is not directly related but still cool read up on "The Monty Hall Problem".
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Old 03-30-2012, 12:27 AM   #17
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Quote:
Originally Posted by Yunus

That's exactly how it works. There are 175,711,536 combinations possible. Buy all the possible combinations and your combined odds of winning are 175,711,536:175,711,536 or 1:1. You can't simply "buy that many tickets" you would need to buy that many tickets with no duplicates.

http://mathforum.org/library/drmath/view/56691.html

For a really interesting concept that is not directly related but still cool read up on "The Monty Hall Problem".
I read the link, that makes since. In the lottery he was talking about you have a 1 in 14,000,000 chance with 1 ticket. If you buy 100 tickets you have a 100 in 14,000,000 chance. Long odds but they do increase in your favor.

Chandler says, no matter how many you buy, your odds remain the same. I understand each ticket would be the same odds individually. If you buy 100 tickets, the odds of your agregate purchase has to go up accordingly, atleast in my head.
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Old 03-30-2012, 12:29 AM   #18
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Quote:
Originally Posted by Chandler51

Odds remain the same. Otherwise, the "1:189,000,000 odds (or whatever they are) would mean, buy that many tickets and you're a guaranteed winner. Sorry, doesn't work that way.

The odds are the same, no matter the number of tix purchased, counterintuitive as that may be.

I don't think that's correct,and I'll use Souths explanation of your theory to disprove it.

Quote:
Originally Posted by downsouth

So if there are 19 black marbles and 1 white marble in a hat. My odds are the same for picking the white marble, no matter how many tries I get? This is alittle easier to get my head around.
You basically got it with your marbles explanation,except that once you pick a black marble (non-winning ticket) you keep it out of the hat (wherever you would put 175 million lottery tickets) because you would no longer have to pick that marble/combination again. The only difference would be that instead of 20 marbles,you would have 175 million tickets,and since you wouldn't know which ticket was the "white marble" until the drawing you would have to buy all 175 million ticket combinations. Kind of like if your white marble was painted black,you just pick all twenty marbles,and you know you have the white one... Then spray them all with paint thinner to see which one is the white one.


So if you can understand that that is how it should work....


..... I think

Maybe there was to much marble analogy in that.

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Old 03-30-2012, 12:30 AM   #19
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Quote:
Originally Posted by Yunus

That's exactly how it works. There are 175,711,536 combinations possible. Buy all the possible combinations and your combined odds of winning are 175,711,536:175,711,536 or 1:1. You can't simply "buy that many tickets" you would need to buy that many tickets with no duplicates.

http://mathforum.org/library/drmath/view/56691.html

For a really interesting concept that is not directly related but still cool read up on "The Monty Hall Problem".
So, you're telling me that nobody with that much dough is willing to spend it for a GUARANTEED eight figure payday?

South had the right idea...an extra "chance" does not increase the odds.
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Old 03-30-2012, 12:33 AM   #20
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I understand the Monty python thing...however it doesn't apply here. It is interesting, however.

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